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Alkane

AP Chem Final Review

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Chemistry Final Review By: AP Chemistry Class Nuclear...Some Definitions ? Nucleons-any particle found in the nucleus - ex(protons and neutrons) ? Nuclide-atom defined by # of protons and neutrons in nucleus ? Isotopes-same # of protons, but different # of neutrons ? Attraction stronger in nucleus than repulsion ? Hideki Yukawa Nuclear Types of forces: ? Strong Nuclear Force-interaction that binds nucleons together when very close...short distances=larger nuclei Nuclear Binding energy: ? When protons and neutrons come together, energy released ? More stable=Lower Energy ? Nuclear Binding energy-energy released when nucleons come together ? Mass of atom < combined masses of separate parts

AP Chem Study Guide

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Chemistry Final Review By: AP Chemistry Class Nuclear...Some Definitions ? Nucleons-any particle found in the nucleus - ex(protons and neutrons) ? Nuclide-atom defined by # of protons and neutrons in nucleus ? Isotopes-same # of protons, but different # of neutrons ? Attraction stronger in nucleus than repulsion ? Hideki Yukawa Nuclear Types of forces: ? Strong Nuclear Force-interaction that binds nucleons together when very close...short distances=larger nuclei Nuclear Binding energy: ? When protons and neutrons come together, energy released ? More stable=Lower Energy ? Nuclear Binding energy-energy released when nucleons come together ? Mass of atom < combined masses of separate parts

Organic Chapter 4 ppt

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Chapter 4 The Study of Chemical Reactions Organic Chemistry, 6th Edition L. G. Wade, Jr. Chapter 4 * Introduction Reactants ? Products: overall reaction. Mechanism: complete step-by-step description of exactly which bonds break and form in what order to give observed products To learn more about a reaction: Thermodynamics Kinetics. => Chapter 4 Chapter 4 * Thermodynamics study of energy changes provides an opportunity to: compare stability of reactants and products predict which compounds are favored Kinetics study of reaction rates, determining which products form the fastest helps predict how the rate will change if conditions are changed Chapter 4 Chapter 4 * Chlorination of Methane

Organic Chapter 3 ppt

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Chapter 3 Structure and Stereochemistry of Alkanes Organic Chemistry, 6th Edition L. G. Wade, Jr. Chapter 3 * Classification Review Chapter 3 Chapter 3 * Alkane Formulas All C-C single bonds Saturated with hydrogens Ratio: CnH2n+2 Alkane homologs: CH3(CH2)nCH3 Same ratio for branched alkanes => Chapter 3 Chapter 3 * Common Names Isobutane, ?isomer of butane? Isopentane, isohexane, etc., methyl branch on next-to-last carbon in chain. Neopentane, most highly branched Five possible isomers of hexane, 18 isomers of octane and 75 for decane! => Chapter 3 Chapter 3 * Alkane Examples => Chapter 3 Chapter 3 * IUPAC Names Find the longest continuous carbon chain.

Campbell Biology Chapter 4 Study Guide

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Name Period Chapter 4: Carbon and the Molecular Diversity of Life Concept 4.1 Organic chemistry is the study of carbon compounds 1. Study this figure of Stanley Miller?s experiment to simulate conditions thought to have existed on the early Earth. Explain the elements of this experiment, using arrows to indicate what occurs in various parts of the apparatus. What was collected in the sample for chemical analysis? What was concluded from the results of this experiment? Concept 4.2 Carbon atoms can form diverse molecules by bonding to four other atoms Make an electron distribution diagram of carbon. It is essential that you know the answers to these questions: How many valence electrons does carbon have? How many bonds can carbon form?

Stereo chemistry of organic compounds

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Organic Chemistry Stereochemistry of Organic Compounds Dr. Anita Tandon University of Delhi Delhi -110007 CONTENTS Structural Isomers Stereoisomers Conformational Isomers Configurational Isomers (i) Optical isomers (a) Compound with one Asymmetric Carbon Atom (b) Compound with more than one Asymmetric Carbon Atom (c) Compound with no Asymmetric Carbon Atom (d) Elements of Symmetry (e) Properties of Enantiomers (f) Relative Configuration (g) Absolute Configuration (h) Fischer?s Plane Projection Diagram (i) Optical inactivity in compounds having Chiral Carbon Atom (ii) Geometrical Isomers (a) E&Z system of nomenclature (b) Properties of Geometrical Isomers

SAT Chem Orgo

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Carbon and Organic Chemistry Carbon?Three allotropic forms: Diamond, graphite, and amorphous Fullerens?New allotropic form of carbon?Near sperical cages of carbon atoms Diamond?Close-pakced crystal structure that gives a property of extreme hardness Carbon?Bonded to four other carbons in a tetraheral arragement Almost endless number of covalent ponds All bonds in this structure are equally strong, therefore very hard and notriously difficult to melt Diamond?Melting point at 3,550 degrees celsius. Synthetic diamonds can be made by putting carbon to extremely high pressurs and temperature Graphite form is made up of planes of hexagonal structures that are wealkly bonded to the planes above and below?Explains the slippery feeling of graphite
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