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Natural logarithm

Population Growth Questions

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Bio 270 Practice Population Growth Questions 1 Population Growth Questions Answer Key 1. Distinguish between exponential and logistic population growth. Give the equations for each. Exponential growth is continuous population growth in an environment where resources are unlimited; it is density-independent growth. dN/dt = rN where, dN/dt = change in population size; r = intrinsic rate of increase (= per capita rate of increase and equals birth rate minus death rate); N = population size. Nt = Noert where, Nt = population size at time t; No = original population size, r = intrinsic rate of increase and t = time Logistic growth is continuous population growth in an environment where resources are

2_logarithmic_functions_1

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Section 3.2 Logarithmic Functions 1 Section 3.2 Logarithmic Functions (Complete problems in purple before class) Definition: Logarithmic Function For a > 0 and a ? 1, the logarithmic function with base a denoted f ( x) = log a ( x), where ? = log?(?) if and only if ? ? = ? Note that log a( 1) = 0 for any base a, because a 0 = 1 for any base a. ? There are two bases that are used more frequently than others; they are 10 and e. ? The notation log 10( x) is abbreviated log( x) and log e( x) is abbreviated ln( x), which are called common logarithms and natural logarithms, respectively. Note: log x means x10log : base 10 ln e means xelog : base e One-to-One Property of Logarithms

Calculus AB #4

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Ws 4 ? TRIG VALUES Show your work in your NOTEBOOK! 1. Solve each such that 0 2x ?? ? . a. 3tan 3x ? b. 1sin 2x ? c. 3cos 2x ? d. tan 1x ? ? e. sin 1x ? ? f. cos 0x ? g. 2sin 2x ?? h. csc 2x ? ? i. 2 3sec 3x ? ? j. tan x is undefined. k. cot 0x ? 2. Solve each equation such that 0 2x ?? ? . a. 2cot cot 0x x? ? b. 22cos 7cos 4x x? ? c. 2 2cos sin sin 0x x x? ? ? d. 2 22sin 5sin 3sin 0x x x? ? ? e. 2sin 2cos 2x x? ? f. 24cos 1x ? g. 23cos 3 2sinx x? ? 3. RECALL! Evaluate each. a. 11sin 6 ? b. 3sin 2 ? c. cos? d. 2tan 3 ? e. csc 3 ? f. 4cos 3 ? 4. Solve each such that 0 2x ?? ? . Round each to 3 decimal places. a. sin 0.231x ? b. csc 2.675x ?? c. tan 0.219x ?? d. cot 1.290x ?

AP Calc Study Guide

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Copyright 1996,1997 Elaine Cheong All Rights Reserved Study Guide for the Advanced Placement Calculus AB Examination By Elaine Cheong 1 Table of Contents INTRODUCTION 2 TOPICS TO STUDY 3 ? Elementary Functions 3 ? Limits 5 ? Differential Calculus 7 ? Integral Calculus 12 SOME USEFUL FORMULAS 16 CALCULATOR TIPS AND PROGRAMS 17 BOOK REVIEW OF AVAILABLE STUDY GUIDES 19 ACKNOWLEDGEMENTS 19 2 Introduction Advanced Placement1 is a program of college-level courses and examinations that gives high school students the opportunity to receive advanced placement and/or credit in college. The Advanced Placement Calculus AB Exam tests students on introductory differential and integral calculus, covering a full-year college mathematics course.

Trig formula sheet

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All Rights Reserved: http://regentsprep.org Algebra 2 ? Things to Remember! Exponents: 0 1x ? 1m m x x ? ? ?m n m nx x x ?? ?( )n m n mx x? m m n n x x x ?? n n n x x y y ? ? ?? ?? ? ( ) ?n n nxy x y? Complex Numbers: 1 i? ? ; 0a i a a? ? ? 2 1i ? ? 14 2 1i i? ? ? divide exponent by 4, use remainder, solve. ( ) conjugate ( )a bi a bi? ? 2 2( )( )a bi a bi a b? ? ? ? 2 2a bi a b? ? ? absolute value=magnitude Logarithms log yby x x b? ? ? ln logex x? natural log e = 2.71828? 10log logx x? common log Change of base formula: log log logb a a b

Ch9 SG

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372 CHAPTER 9 Mathematical Modeling with Differential Equations EXERCISE SET 9.1 1. y? = 2x2ex 3/3 = x2y and y(0) = 2 by inspection. 2. y? = x3 ? 2 sinx, y(0) = 3 by inspection. 3. (a) ?rst order; dy dx = c; (1 + x) dy dx = (1 + x)c = y (b) second order; y? = c1 cos t? c2 sin t, y?? + y = ?c1 sin t? c2 cos t+ (c1 sin t+ c2 cos t) = 0 4. (a) ?rst order; 2 dy dx + y = 2 ( ? c 2 e?x/2 + 1 ) + ce?x/2 + x? 3 = x? 1 (b) second order; y? = c1et ? c2e?t, y?? ? y = c1et + c2e?t ? ( c1et + c2e?t ) = 0 5. 1 y dy dx = x dy dx + y, dy dx (1? xy) = y2, dy dx = y2 1? xy 6. 2x+ y2 + 2xy dy dx = 0, by inspection. 7. (a) IF: ? = e3 ? dx = e3x, d dx [ ye3x ] = 0, ye3x = C, y = Ce?3x separation of variables: dy y = ?3dx, ln |y| = ?3x+ C1, y = ?e?3xeC1 = Ce?3x

Ch8 SG

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317 CHAPTER 8 Principles of Integral Evaluation EXERCISE SET 8.1 1. u = 3? 2x, du = ?2dx, ? 1 2 ? u3 du = ?1 8 u4 + C = ?1 8 (3? 2x)4 + C 2. u = 4 + 9x, du = 9dx, 1 9 ? u1/2 du = 2 3 ? 9u 3/2 + C = 2 27 (4 + 9x)3/2 + C 3. u = x2, du = 2xdx, 1 2 ? sec2 u du = 1 2 tanu+ C = 1 2 tan(x2) + C 4. u = x2, du = 2xdx, 2 ? tanu du = ?2 ln | cosu |+ C = ?2 ln | cos(x2)|+ C 5. u = 2 + cos 3x, du = ?3 sin 3xdx, ? 1 3 ? du u = ?1 3 ln |u|+ C = ?1 3 ln(2 + cos 3x) + C 6. u = 3x 2 , du = 3 2 dx, 2 3 ? du 4 + 4u2 = 1 6 ? du 1 + u2 = 1 6 tan?1 u+ C = 1 6 tan?1(3x/2) + C 7. u = ex, du = exdx, ? sinhu du = coshu+ C = cosh ex + C 8. u = lnx, du = 1 x dx, ? secu tanu du = secu+ C = sec(lnx) + C 9. u = cotx, du = ? csc2 xdx, ? ? eu du = ?eu + C = ?ecot x + C
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