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polynomials

polynomial functions

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6.6 Zeros, Factors, and Solutions Name__________________________ Algebra 2 Date____________Per____________ Find the missing factors: 1. 2. 3. 4. Write a polynomial function that has the given zeros and a leading coefficient of 1: 5. 6. Graph each: 7. 8. 9. 10. 11. 12. _1258988827.unknown _1284793318.unknown _1284793376.unknown _1263285822.unknown _1263285844.unknown _1261237811.unknown _1263285812.unknown _1260889911.unknown _1258988669.unknown _1258988826.unknown _1258988613.unknown _1076349005.unknown

alg2 review

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H/GT Algebra II - Semester Exam Final Review 1.) Solve 4 264 16 1 0b b? ? ? 2.) What is the vertex of 23 24 5y x x? ? ?? 3.) Graph 22( 1) 1y x? ? ? 4.) Solve 25 19 4n n? ? 5.) Write an equation of a parabola that passes through the points (0, 2), (-2, 6), and (6, 14). 6.) Write the equation for the graph below. 7.) Write an equation of a parabola (general form) with vertex (0, 0) and directrix y = 2. 8.) Find the vertex of 24 4x y y? ? 9.) Graph 2 3y x? ? 10.) Write an equation of a circle with center (4, -3) and radius 5. (General form) 11.) Find the center and radius: 2 2 8 4 12 0x y x y? ? ? ? ?

INTERMEDIATE ALGEBRA EXAM

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MATH EXAM 1 THRU 4 1 MATH EXAM #1 1. Determine whether the diagram defines y as a function of x. if it does not, indicate a value x that is assigned more than one value of y X y -4 5 -3 7 4 9 4 11 2. GRAPH THE FUNCTION: h(x) =|4-x| X h(x) 3 1 4 0 5 1 6 2 2 2 1 3 3. Determine the graph of the solution of the given system. X + Y > 2 X - Y < 2 MATH EXAM 1 THRU 4 2 3 Determine whether the graph is a function 4. THE GRAPH OF A SYSTEM OF 2 LINEAR INEQUALITES IS SHOWN. TELL WHICH POINT IS A SOLUTION OF THE SYSTEM. MATH EXAM 1 THRU 4 3 6. FIND THE SOLUTION OF THE SYSTEM. X > -2 Y > -4

UPDATED EXAM INTERMEDIATE ALGEBRA

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MATH EXAM 1 THRU 3 1 MATH EXAM #1 1. Determine whether the diagram defines y as a function of x. if it does not, indicate a value x that is assigned more than one value of y X y -4 5 -3 7 4 9 4 11 2. GRAPH THE FUNCTION: h(x) =|4-x| X h(x) 3 1 4 0 5 1 6 2 2 2 1 3 3. Determine the graph of the solution of the given system. X + Y > 2 X - Y < 2 MATH EXAM 1 THRU 3 2 3 Determine whether the graph is a function 4. THE GRAPH OF A SYSTEM OF 2 LINEAR INEQUALITES IS SHOWN. TELL WHICH POINT IS A SOLUTION OF THE SYSTEM. MATH EXAM 1 THRU 3 3 6. FIND THE SOLUTION OF THE SYSTEM. X > -2 Y > -4

FORMULAS AND FUNCTIONS/RADICAL EXP AND EQUATION/ QUAD EQU, FUNCTION& INEQU

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MATH EXAM 1 1 MATH EXAM #1 1. Determine whether the diagram defines y as a function of x. if it does not, indicate a value x that is assigned more than one value of y X y -4 5 -3 7 4 9 4 11 2. GRAPH THE FUNCTION: h(x) =|4-x| X h(x) 3 1 4 0 5 1 6 2 2 2 1 3 3. Determine the graph of the solution of the given system. X + Y > 2 X - Y < 2 MATH EXAM 1 2 3 Determine whether the graph is a function 4. THE GRAPH OF A SYSTEM OF 2 LINEAR INEQUALITES IS SHOWN. TELL WHICH POINT IS A SOLUTION OF THE SYSTEM. MATH EXAM 1 3 6. FIND THE SOLUTION OF THE SYSTEM. X > -2 Y > -4 7. GRAPH THE SOLUTIONS OF THE SYSTEM

FINAL EXAM- FORMULAS/EQUATION/INEQUALTIES/EXPONENTIAL AND LOG FUNCTIONS/SYSTEMS OF EQUATIONS,QUADRATIC EQUATIONS,FUNCTIONS,INEQU

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MATH EXAM 1 THRU 4 1 MATH EXAM #1 1. Determine whether the diagram defines y as a function of x. if it does not, indicate a value x that is assigned more than one value of y X y -4 5 -3 7 4 9 4 11 2. GRAPH THE FUNCTION: h(x) =|4-x| X h(x) 3 1 4 0 5 1 6 2 2 2 1 3 3. Determine the graph of the solution of the given system. X + Y > 2 X - Y < 2 MATH EXAM 1 THRU 4 2 3 Determine whether the graph is a function 4. THE GRAPH OF A SYSTEM OF 2 LINEAR INEQUALITES IS SHOWN. TELL WHICH POINT IS A SOLUTION OF THE SYSTEM. MATH EXAM 1 THRU 4 3 6. FIND THE SOLUTION OF THE SYSTEM. X > -2 Y > -4

Practice Test on Algebraic Equations and Functions

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An equivalent expression to the algebraic expression 9x2 ? 4y2 is: A) 3x ? 2y B) 6(3x2 ? 2y2) C) (3x + 2y)(3x ? 2y) D) (2y + 3x)(2y ? 3x) Correct. Your answer=C, Correct answer=C Explanation: 9x2 ? 4y2 = (3x + 2y)(3x ? 2y) Factor the trinomial x2 ? 2x ? 15: A) (x ? 3)(x ? 5) B) (x + 3)(x ? 5) C) (x ? 3)(x + 5) D) (x + 3)(x + 5) Correct. Your answer=B, Correct answer=B Explanation: The numbers ?5 and 3 multiply to give ?15 and add to give ?2. x2 ? 2x ? 15 = x2 ? 5x +3x ? 15 = x (x ? 5) + 3 (x ? 5) = (x ? 5)(x + 3) Fully factored, the quadratic function y = 2x2 + 10x + 12 can be expressed as: A) y = 2(x + 6)(x + 2) B) y = 2(x + 3)(x + 2) C) y = 2(x + 6)(x + 1) D) y = 2(x + 3)(x + 1) Correct. Your answer=B, Correct answer=B Explanation: y = 2x2 + 10x + 12 y = 2(x2 + 5x + 6)

great minds

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Alexander, James Waddell, II born September 19, 1888, Sea Bright, New Jersey, U.S. ? died September 23, 1971, Princeton, New Jersey American mathematician and a founder of the branch of mathematics originally known as analysis situs, now called topology.

Math Algebra

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CALIFORNIA CONTENT STANDARDS: ALGEBRA I # of Items % Symbolic reasoning and calculations with symbols are central in algebra. Through the study of algebra, a student develops an understanding of the symbolic language of mathematics and the sciences. In addition, algebraic skills and concepts are developed and used in a wide variety of problem-solving situations. N/A N/A Algebra I 65 100% Standard Set 1.0 Students identify and use the arithmetic properties of subsets of integers and rational, irrational, and real numbers, including closure properties for the four basic arithmetic operations where applicable: N/A 1.1 Students use properties of numbers to demonstrate whether assertions are true or false. 1/2**

How to Factor Trinomial with Leading Coefficient of One, Part One

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First, organize the polynomial in terms of order (2nd, 1st, and 0). Then, note the signs between each term of the polynomial. If the second sign is positive, then the signs between each term of each resulting binomial will be the same. You can determine this sign by looking at the first algebraic sign between terms. If the sign is positive, both signs will be positive. If the sign is negative, both signs will be negative. If the second sign is negative, both signs in the resulting binomials will be opposite. If the first sign is positive, then the sign next to the biggest constant in the binomial will be positive, and vice versa.

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