Few things i need help with before my Alg II honors final. i need a decent grade on this thing. thanks
Lol so first thing......Solving Complex expressions and quadratic equations and wiritng them in the form a+bi???
-i know what i is, but i dont understand everything about how to solve stuff with it, and what the standard form a+bi means
Ex: sqrt(-4) * sqrt (-4)
Ex: 6x^2-48x+192=0
and then...the functions where there are 2 of them at once bracketed by a { ??? if you go to graph them, do u just graph them both seperately? and are these the same as piecewise defined functions?
No examples of this that i can find
theres something about functions thats in the form f(a+h) - f(a), all of that over h?......how do u solve these?
then finally, could someone walk me thru doing long division with expressions? i understand synthetic division, but the long stuff loses me
Ex: 6x^3 + 6x^2 +12x/
3x^2+4
??? lol you dont have to answer everything, any help is appreciated
thanks
well sqrt(-4) is just 2i, this process involves taking the negative out so for example sqrt(-225) is just 15i and you leave your answer as that
for your 2nd problem 6x^2-48x+192=0 take it step by step you can either do qud form
(x= (plus or min) (-b*sqrt(b^2-4ac))/2a or you can make it a perfect squared.
6x^2-48x= -192 sub 192 from both sides
x^2-8x= -32 divide by 6
x^2-8x+16= -16 divide 8 by 2 then square the 4 you get then add to both sides
(x-4)(x-4)=-16
(x-4)^2= -16
x-4= 4i
x=4i+4
x= 4i-4 this is because when u take the sqroot of somthing u plus or minus it
HOPE THIS HELPS im only a jr in hs In Calc 2 so PM if u need help with other things
well sqrt(-4) is just 2i, this process involves taking the negative out so for example sqrt(-225) is just 15i and you leave your answer as that
for your 2nd problem 6x^2-48x+192=0 take it step by step you can either do qud form
(x= (plus or min) (-b*sqrt(b^2-4ac))/2a or you can make it a perfect squared.
6x^2-48x= -192 sub 192 from both sides
x^2-8x= -32 divide by 6
x^2-8x+16= -16 divide 8 by 2 then square the 4 you get then add to both sides
(x-4)(x-4)=-16
(x-4)^2= -16
x-4= 4i
x=4i+4
x= 4i-4 this is because when u take the sqroot of somthing u plus or minus it
HOPE THIS HELPS im only a jr in hs In Calc 2 so PM if u need help with other things